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Bolt Tensile & Shear Strength Calculator

Calculate the ultimate tensile load of metric bolts from ISO 898-1 property-class data, plus a simplified shear capacity estimate. Select bolt size and property class.

ISO 898-1 M3 – M64 Class 4.6 – 12.9
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Results

Ultimate Tensile Load (Ft)
Shear Capacity (Fs, simplified estimate)
Tensile Stress Area (As)
Yield Load (Fy)
Ultimate Tensile Strength (Rm)

Ultimate Tensile Load

The maximum tensile force a bolt can sustain before fracture:

  • Rm — ultimate tensile strength (MPa), from property class
  • As — tensile stress area (mm²), from ISO 898-1 / ISO 261

Shear Capacity (Simplified Estimate)

ISO 898-1 defines the tensile and proof-load properties of bolts — it does not specify shear strength. The value shown here is a widely used simplified engineering estimate that takes shear strength as approximately 60% of tensile strength (based on the von Mises criterion, τ ≈ 0.58 σ):

For double shear, multiply by 2 (two shear planes).

⚠️ Shear design note: Actual shear capacity depends on whether the shear plane passes through the threads or the unthreaded shank, on joint slip and plate bearing, and on fatigue loading. Design codes define their own values — e.g. Eurocode 3 (EN 1993-1-8) uses Fv = αv × fub × A with αv = 0.6 for classes 4.6, 5.6 and 8.8 but 0.5 for classes 4.8, 5.8, 6.8 and 10.9, together with partial safety factors. Always verify shear-loaded joints against the applicable structural or mechanical design code, not this simplified estimate alone.

Property Classes per ISO 898-1

ClassRm (MPa)Rp0.2 (MPa)Typical Use
4.6400240Low-strength, general purpose
5.8520420Structural, non-preloaded
8.8800640Automotive, machinery (most common)
10.91040940High-strength structural
12.912201100Maximum strength (alloy steel)

Practical Example

Example — M10 × 8.8 Bolt

Given: M10 bolt, property class 8.8, single shear

As = 58.0 mm², Rm = 800 MPa

Ft = 800 × 58.0 = 46,400 N = 46.4 kN

Fs = 0.6 × 800 × 58.0 = 27,840 N = 27.8 kN

⚠️ Note: These are ultimate capacities without safety factors. Apply appropriate safety factors (typically 2–3 for static, 4–6 for fatigue) for design purposes.

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