Free Engineering Tool
Cable Cross-Section Calculator
Determine the correct wire size (mm²) based on current, cable length, voltage, and allowable voltage drop. Round up to nearest standard IEC size automatically.
Results
Cable Cross-Section Formula
The minimum required conductor cross-section to stay within the allowable voltage drop is:
- k — system factor: 2 for single-phase AC and DC, √3 for three-phase AC
- ρ — resistivity of conductor (Ω·mm²/m): Cu = 0.0175, Al = 0.0283
- I — current (A)
- L — one-way cable length (m)
- Vdrop — allowable voltage drop (V)
Allowable Voltage Drop
Actual Voltage Drop
Once a standard cable size Astd is selected:
Standard Cable Sizes (IEC 60228)
| mm² | AWG (approx.) | mm² | AWG (approx.) |
|---|---|---|---|
| 0.75 | 18 AWG | 25 | 4 AWG |
| 1.0 | 17 AWG | 35 | 2 AWG |
| 1.5 | 15 AWG | 50 | 1/0 AWG |
| 2.5 | 13 AWG | 70 | 2/0 AWG |
| 4 | 11 AWG | 95 | 3/0 AWG |
| 6 | 9 AWG | 120 | 4/0 AWG |
| 10 | 7 AWG | 150 | 300 MCM |
| 16 | 5 AWG | 185 | 350 MCM |
Practical Example
Given: I = 10 A, L = 30 m, V = 230 V, max drop = 3%, copper
Vdrop(allowed) = 230 × 3/100 = 6.9 V
A = 2 × 0.0175 × 10 × 30 / 6.9 = 1.52 mm²
Standard size: 2.5 mm² (rounded up)
Actual Vdrop = 2 × 0.0175 × 10 × 30 / 2.5 = 4.2 V = 1.83%
⚠️ Note: This calculator sizes cable based on voltage drop only. Always verify that the selected cable size also meets the current-carrying capacity (ampacity) requirements per local electrical codes (e.g., IEC 60364, NEC).
Cable cross-section is calculated using the formula: A = (k × ρ × I × L) / Vdrop, where k is a system factor (2 for single-phase/DC, √3 for three-phase), ρ is the conductor resistivity, I is current, and L is one-way cable length.
The calculated value should be rounded up to the next standard IEC 60228 size to ensure the actual voltage drop stays within limits.
Excessive voltage drop causes equipment to receive less than its rated voltage, leading to:
- Motor overheating and reduced torque
- Dimming or flickering of lights
- Malfunction of sensitive electronic equipment
- Increased energy losses in the cable
Most electrical codes (IEC 60364, NEC) recommend keeping voltage drop below 3–5% from the supply point to the load.
Copper (ρ = 0.0175 Ω·mm²/m) has lower resistivity than aluminum (ρ = 0.0283 Ω·mm²/m), meaning copper cables need smaller cross-sections for the same current. However:
- Copper: Better conductivity, smaller size, easier to terminate, longer life
- Aluminum: Lighter weight (~30% of copper), significantly cheaper, preferred for large power distribution
For the same current capacity, aluminum requires approximately 1.6× the cross-section of copper.
Standard cable cross-sections per IEC 60228 are:
- Small: 0.75, 1.0, 1.5, 2.5, 4, 6 mm²
- Medium: 10, 16, 25, 35, 50 mm²
- Large: 70, 95, 120, 150, 185, 240, 300 mm²
Always round up the calculated cross-section to the next standard size — never round down.
Common AWG to mm² conversions:
- 14 AWG ≈ 2.08 mm² (closest standard: 2.5 mm²)
- 12 AWG ≈ 3.31 mm² (closest standard: 4 mm²)
- 10 AWG ≈ 5.26 mm² (closest standard: 6 mm²)
- 8 AWG ≈ 8.37 mm² (closest standard: 10 mm²)
- 6 AWG ≈ 13.3 mm² (closest standard: 16 mm²)
- 4 AWG ≈ 21.2 mm² (closest standard: 25 mm²)
- 2 AWG ≈ 33.6 mm² (closest standard: 35 mm²)
- 1/0 AWG ≈ 53.5 mm² (closest standard: 50 mm²)
- 4/0 AWG ≈ 107 mm² (closest standard: 120 mm²)
The formula is: mm² = 0.012668 × 92((36−AWG)/19.5)
The procedures described on this page were developed and field-tested by the Vibromera team using the Balanset-1A, a portable dual-channel balancer and vibration analyzer for on-site rotor balancing.
Professional field balancing instruments and software. Used in 50+ countries for industrial maintenance.