Ninahesabuje nguvu ya kipasha joto?

P = m × c × ΔT / t, where P is power (W), m is mass (kg), c is specific heat (J/kg·K), ΔT is temperature rise (K or °C), and t is heating time (s). For water: c = 4186 J/kg·K.

Nguvu kiasi gani inahitajika kupasha joto lita 100 za maji?

100L of water = 100kg. To heat by 50°C in 1 hour: P = 100 × 4186 × 50 / 3600 = 5,814W ≈ 6kW. Add 10-20% for losses.

Joto maalum la maji na viowevu vya kawaida ni ngapi?

Water: 4186 J/kg·K. Air: 1005 J/kg·K. Oil (thermal): ~2000 J/kg·K. Glycol 50%: ~3300 J/kg·K. Ethanol: 2440 J/kg·K.

Je, ninapaswa kuongeza kiasi cha usalama kwa nguvu ya kipasha joto?

Ndiyo. Ongeza 10-20% kwa ajili ya upotevu wa joto kupitia kuta za chombo na mabomba. Kwa matangi ya nje, ongeza 30-50%. Kwa upashaji joto wa awamu na kuanza baridi, zingatia mahitaji ya kilele.

Ninabadilishaje kati ya ujazo na uzito?

mass = volume × density. Water: 1 kg/L. Air at 20°C: 1.204 kg/m³. Thermal oil: ~0.85 kg/L. Always use the density at the average temperature.

Zana ya Uhandisi Isiyolipisha

Kikokotoo cha Nguvu ya Heater

Calculate the power required to heat a liquid or air. P = m × c × ΔT / t. Enter mass or volume, specific heat, temperature rise, and heating time.

P = m·c·ΔT/tKioevu & Hewa#177

Results

Required Power

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Total Energy

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Mass

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Pamoja na Hasara za 15%

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Fomula ya Nguvu ya Kupasha Joto

Where m = mass (kg), c = joto mahsusi (J/kg·K), ΔT = ongezeko la halijoto (°C), t = muda (sekunde).

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