Meet Vibromera.com — our new international website. Visit Vibromera.com →

Reference worksheet · fixed-axis rigid-body model

Uniform-Shape Axial Mass-Moment-of-Inertia Worksheet

Calculate mass moment of inertia about the stated centroidal spin axis for one uniform ideal solid cylinder/disc, annular cylinder, or solid sphere.

J = ∫r⊥²dmdocumented mass or density helperstrict unitsno acceptance verdict
Axis and model first. These are general classical-mechanics formulas, not an ISO or API calculation. They do not represent a stepped, bladed, keyed, slotted, eccentric or assembled rotor unless that real mass distribution is actually equivalent to the selected ideal shape about the stated axis.

Controlled inputs

Use documented mass when available. The density helper is only for a uniform homogeneous shape. Changing a unit clears its paired numeric field and the previous result, so a number is never silently reinterpreted.

Documented-mass solid cylinder/disc: enter component mass and outer diameter. Axial length does not enter J once mass is documented.
Required model confirmation

Reference result

Axial mass moment of inertia J
Component mass
Radius of gyration k = √(J/m)
No pass/fail, acceleration, energy, balancing or safe-speed conclusion is produced. Apply the result only to the documented axis and idealized component.

Equations, units and model boundary

Mass moment of inertia about a specified fixed axis is J = ∫r⊥²dm, where r⊥ is perpendicular distance from each mass element to that axis. The same body generally has different inertia about a different axis.

Centroidal axial formulas used here

solid cylinder/disc: Jz = ½mR²  ·  annular cylinder: Jz = ½m(Ro² + Ri²)  ·  solid sphere: J = ⅖mR²

R = D/2 and Ri = d/2. The cylinder formulas are only for the central longitudinal symmetry axis. The sphere formula applies to a diameter through its center.

Optional uniform-density helper

m = ρπR²L  ·  m = ρπ(Ro²−Ri²)L  ·  m = ρ(4πR³/3)

The helper derives mass only for a homogeneous full solid/annular cylinder or solid sphere. Length does not appear in axial J once mass is known, but in density mode it changes mass and therefore J.

Exact unit normalization

The worksheet calculates in kg·m² and reports exact derived equivalents. In particular, 1 kg·m² = 10⁹ g·mm²; 1 in = 0.0254 m and 1 lbm = 0.45359237 kg exactly. “lbm·ft²” is used, not the ambiguous label “lb·ft²”.

Offset and composite rotors

The parallel-axis theorem is J = Jcm + m d⊥², where d⊥ is the perpendicular distance between parallel axes. It is not a substitute for defining the final common axis. Composite rotors may require signed material/void components, coordinate transformations, CAD mass properties or direct inertia measurement; this worksheet does not sum components.

Independent published check

University Physics (UCF/OpenStax) gives a coaxial system consisting of a 2.0 kg, 0.50 m-radius disk and a 1.0 kg annular cylinder with 0.20/0.30 m inner/outer radii; its published total is 0.315 kg·m². Two documented-mass worksheet runs give 0.250 kg·m² and 0.065 kg·m², whose controlled sum reproduces 0.315 kg·m². This checks the formulas; it does not authorize using this single-component worksheet as a general rotor assembly model.

Source classification

ClaimPhân loạiInspected source
J = ∫r⊥²dm; disk/cylinder ½mR²; sphere ⅖mR²; axis dependenceGeneral classical mechanics; not an ISO formulaMIT OCW 8.01L lecture 28, rendered page 2
Annular cylinder ½m(Ro²+Ri²)Integrated uniform thick cylindrical shellUniversity of Illinois Engineering Dynamics Reference
Parallel-axis J = Jcm + md⊥²General classical mechanics; perpendicular separation between parallel axesMIT OCW 8.01L lecture 28, rendered page 2
0.315 kg·m² disk-plus-annulus checkPublished university textbook exampleUCF Pressbooks / OpenStax University Physics, section 10.4
inch, pound-mass and lbm·ft² conversion basisMetrology / unit conversionNIST SP 811 Appendix B.8

Accessed: 14 July 2026. The cited MIT page was rendered and visually inspected. No ISO or API acceptance criterion is implemented.

Questions this worksheet does not answer

Is this the inertia of my complete rotor?

Only if its actual mass distribution about the stated axis is represented by this one ideal uniform shape. Real rotors commonly require CAD/FE mass properties, a controlled component sum or direct measurement.

Can I use the result for transverse bending or rocking?

No. The cylinder/disc result here is about the central longitudinal spin axis. Transverse moments contain different radius and length terms.

Why are material presets absent?

Density depends on the controlled alloy, porosity, processing state and temperature. Enter a value from the actual component specification or measurement record.

Revision: scientific audit 2026-07-14 · English source page · Reference calculation only. Preserve the input and source records with the result.
Categories:

WhatsApp
Balanset-1A · 1.975 €Hỏi kỹ sư